(2^2/7)^x=16

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Solution for (2^2/7)^x=16 equation: 


(1/1)*x^1*y^1*z*ln(x^2+y^2+z^2)

x^2+1

2*x

x^1*y^1*z*(ln(x^2+y^2+z^2)/1)

x-(3*y)-15;2*x+4*y-90

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